10x^2+37x-183=0

Solution for 10x^2+37x-183=0 equation:

10x^2+37x-183=0

a = 10; b = 37; c = -183;
Δ = b2-4ac
Δ = 372-4·10·(-183)
Δ = 8689
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-\sqrt{8689}}{2*10}=\frac{-37-\sqrt{8689}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+\sqrt{8689}}{2*10}=\frac{-37+\sqrt{8689}}{20}
$